@mvthedits: 21 is sooooo underrated, watch it now ! | #21 #21movie #blackjack #fyp #viral #edit |

mvthedits
mvthedits
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Tuesday 15 October 2024 18:57:50 GMT
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kingslimesaca
ybg SACA🇦🇴 :
I die on the hill that it is 50%
2024-10-16 18:04:34
12078
dashmater
jan.p :
how does switching make sense? it becomes a 50/50 desicion ?its either 1 or 2nd he can chose whichever?
2024-10-15 22:32:40
1532
.spencerthompson
Spencer Thompson :
This is learned in a high school ap statistics class
2024-10-16 07:10:14
13482
burnerinnit
burnerinnit :
All the people saying its 50/50, just google monty hall proble
2024-10-16 03:14:56
7654
ice_man426
iceman426 :
all this does is show the problem with the study of "statistics". because per the math then yeah that checks out. realistically he turned 33/33/33 into 50/50
2024-10-16 21:23:58
6
iaminsideyourwaiis
randomguy :
took me half a year to accept that this is the correct answer
2024-10-16 21:45:50
1963
mikeonthemic04
mikeonthemic04 :
This doesn't even make sense. Your chance of being right is still 33.3% because you're still only choosing 1 of 3 doors, and that's assuming that the 2nd door offered actually has the prize in it
2024-10-17 13:51:57
2
aussietripsml
HugBunter #1 fan :
if you switch, the only way you lose is if you picked the correct door first. and we know that picking the correct door first is 1/3... so the only way you lose is 1/3.. so winning is 2/3.
2024-10-17 09:30:59
2350
dylan_hogarth
Dylan :
1.the car is on the first door and you chose it but switched so you lost. 2.the car is on the second door and you switched you won. 3. the car is on the third door and you switched you won. 2/3 = 66.6
2024-10-16 12:35:48
1113
ckahte
Akta mannen 🐻🐻‍❄️🐻🐻‍❄️ :
That’s like a high school math question
2024-10-15 23:19:06
2259
eriks_bageri
Erik :
How can it rise to 66% never got that
2024-10-15 22:19:40
136
hafidmahdii
fidudu :
for those who don't understand, to make it more intuitive, lets say we have 52 cards, to win, you need to get ace of hearts, and the host knows all the cards, initially whatever cards you chose, the chance is 1/52, and after that, the host open all other 50 cards, and none of them are ace of hearts, so it left with two cards: your initial choice, and another one which you didn't choose, so, your card, still 1/52 chance and the another card become 50/51 chance to get an ace of hearts
2024-10-16 14:29:08
699
zoomfruit
zoomfruit 🇨🇦 :
The Monty hall problem is more intuitive when it’s like 1000 doors as you gotta remember when they open the other 998 doors they’re deliberately opening doors that don’t have the prize so the question
2024-10-16 21:20:19
630
isimpforabby0
ACoomer :
It’s still 50/50, using their way means when he opens the wrong door it’s 66% for both remaining doors which means it’s equal chance for both…50%
2024-10-16 13:55:00
26
tmftzh
Tiktacwarrior :
Can we actually get 100 trials of this and find the probability or is this a theoretically correct but realistically incorrect
2024-10-16 11:48:31
29
dysregulate
호밀 :
After a door is removed your 66.7% chance of being wrong remains, which means the other door has a 66.7% chance of being right, your 33.3% is fixed probability.
2024-10-16 12:23:22
677
tuttpham6
tuttpham :
Easiest to understand if you pick 1 card out of 52 then remove 50 cards afterwards. Easy to tell you should switch to the only card he didn’t remove because you had 1/52 chance in the beginning 💯
2024-10-16 18:35:30
227
thecobdad
TheCobDad :
i think the part of the monty hall problem is that its never explained well, to fully understand, you need to affirm the game show host, always opens a door with a goat, its not random
2024-10-16 14:02:10
1038
zgannon9
Z.G :
Its actually 50/50 either he does or he does not pick the right door
2024-10-15 23:19:23
21
thecumsta
thecumsta :
Its not real chance tho u dont have to change door to take advantage of the door less. Thats like comparing 5 same coin flips. But at then end of the day its still 50/50 every coin flip.
2024-10-16 15:29:36
6
s1p3.e
Sipe :
key here is: he has the chance to choose, different would be if he had to just pick once and stick with it. The prof will def close one wrong door ehich you dont have to account so 33%
2024-10-16 11:21:47
7
lxvi___
Lxvi___ :
This is 50/50 as he has a choice, if for example they will only show one wrong door and you have to switch after THAT would be a 66.6% chance of success. Because it removes the choice in staying.
2024-10-16 02:22:59
64
jacob_kinchin
Jacob_Sink :
If you don’t understand imagine the same case with 100 doors you pick one I know where the car is and I open 98 of the other doors leaving you the choice to switch you will switch as there’s now a 99%
2024-10-15 23:52:43
433
asshat00
asshat00 :
if one door out of three is picked and confirmed wrong, wouldn’t the percentage be 50/50 for the remaining two doors? cause now it’s fractioned in 2 not in 3
2024-10-15 23:09:33
77
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